The Numbers Game
I have two questions regarding the article Landing at the Max [Airmanship, March] You state: … with a 46 KCAS stall speed. Enter the flare in a 172 at 65 knots instead of 60 and you have 2.25 times as much kinetic energy to dissipate before the airplane will stop flying.
My first question is: How did you compute the factor of 2.25? Here is how I analyze this problem. Kinetic energy is proportional to the square of ground speed. For simplicity Ill assume that CAS is equal to GS. The airplane stops flying at its stall speed of 46 knots, therefore the KE (kinetic energy) that must be dissipated before the airplane will stop flying is the difference between the KE at entry and the KE…